力扣 中等 2300.咒语和药水的成功对数

题目介绍

解法

class Solution {
    public int[] successfulPairs(int[] spells, int[] potions, long success){
        Arrays.sort(potions);
        int n = spells.length, m = potions.length;
        int[] pairs = new int[n];
        for (int i = 0; i < n; i++) {
            int left = 0, right = m - 1;
            long factor = spells[i];
            while (left <= right) {
                int mid = left + (right - left) / 2;
                if ((long) potions[mid] * factor < success) {
                    left = mid + 1;
                } else {
                    right = mid - 1;
                }
            }
            pairs[i] = m - left;
        }
        return pairs;
    }
}

原文地址：https://blog.csdn.net/qq_51352130/article/details/142379261

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