python-数组元素积的符号-LEETCODE
方法一:笨蛋方法,直接相乘
def arraySign(nums):
sum=1
for i in range(len(nums)):
sum=nums[i]*sum
if sum>0:
return 1
if sum<0:
return -1
if sum==0:
return 0
方法二:判断是否有0存在,
def arraySign(nums): sign=1 for i in range(len(nums)): if nums[i]==0: sign=0 if nums[i]<0: sign=-sign return sign print(arraySign([2,3,4,-1,-9,-8,0]))
原文地址:https://blog.csdn.net/hqq1990/article/details/136503607
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