Leetcode—297. 二叉树的序列化与反序列化【困难】

2024每日刷题（148）

Leetcode—297. 二叉树的序列化与反序列化

实现代码

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Codec {
public:

    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
        string ans;

        function<void(TreeNode*)> preorder = [&](TreeNode* root) {
            if(root == nullptr) {
                ans += "null ";
                return;
            }
            
            ans += to_string(root->val) + " ";
            preorder(root->left);
            preorder(root->right);
        };

        preorder(root);
        return ans;
    }

    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        istringstream iss(data);

        queue<string> q;
        for(string s; iss >> s;) {
            q.push(s);
        }

        function<TreeNode*()> preorder = [&]() {
            string node = q.front();
            q.pop();
            if(node == "null") {
                return (TreeNode*)nullptr;
            }

            TreeNode* newNode = new TreeNode(stoi(node));
            newNode->left = preorder();
            newNode->right = preorder();
            return newNode;
        };

        return preorder();
    }
};

// Your Codec object will be instantiated and called as such:
// Codec ser, deser;
// TreeNode* ans = deser.deserialize(ser.serialize(root));

运行结果

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原文地址：https://blog.csdn.net/qq_44631615/article/details/140668316

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