多源字段聚合重塑算法

要求如下

[
    [
        {
            "oone": "评估是否聘请第三方机构",
            "otwo": null,
            "othree": "test",
        },
        {
            "oone": "评估是否聘请第三方机构",
            "otwo": null,
            "othree": "test",
        }
    ],
    [
        {
            "oone": "评估是否聘请第三方机构",
            "otwo": null,
            "othree": "test",
        },
        {
            "oone": "评估是否聘请第三方机构",
            "otwo": null,
            "othree": "test",
        }
    ]
]

<!-- 转换成 -->
[
    {
        "oone": "评估是否聘请第三方机构",
        "otwo": null,
        "othree_1": "test",
        "othree_2": "test"
    },
    {
        "oone": "评估是否聘请第三方机构",
        "otwo": null,
        "othree_1": "test",
        "othree_2": "test"
    }
]

代码实战

function transformData(data) {
  // 确定最终结果数组中的对象数量
  const numObjectsInResult = data[0].length;
  // 使用空对象初始化结果数组
  const result = Array.from({ length: numObjectsInResult }, (_, objIndex) => {
    const firstObjectOfSubArray = data[0][objIndex];
    return { ...firstObjectOfSubArray };
});

  // 迭代原始数据中的每个子数组
  data.forEach((subArray, subArrayIndex) => {
      // 对子数组中的每个对象进行迭代
      subArray.forEach((obj, objIndex) => {
          // 将othree值添加到结果数组中的相应对象
          result[objIndex][`othree_${subArrayIndex + 1}`] = obj.othree;
      });
  });

  return result;
}

const originalData = [
  [
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"}
  ],
  [
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"}
  ],
  [
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"}
  ],
  [
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"}
  ],
  [
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"},
      {"oone": "评估是否聘请第三方机构", "otwo": null, "othree": "test"}
  ]
];

const result = transformData(originalData);
console.log(result);

算法优化

1. 减少数组遍历次数
2. 避免不必要的对象复制
3. 使用Map或对象作为临时存储

function transformData(data) {
  const numObjectsInResult = data[0].length;
  const result = new Map();

  // 初始化Map，添加othree属性的初始值
  data[0].forEach((obj, index) => {
    result.set(index, { ...obj });
    for (let i = 1; i <= data.length; i++) {
      result.get(index)[`othree_${i}`] = null;
    }
  });

  // 遍历data填充othree值
  data.forEach((subArray, subArrayIndex) => {
    subArray.forEach((obj, objIndex) => {
      result.get(objIndex)[`othree_${subArrayIndex + 1}`] = obj.othree;
    });
  });

  // 将Map转换回数组
  return Array.from(result.values());
}

应用场景

1. 在vue中前面几个列可能是固定的, 后边几个列是动态展示
   
   

          <template v-if="questionList.length > 0">
            <el-col class="third-el-col" :style="{width: questionlenght}">
              <el-card>
                <el-table
                  :data="questionListFix"
                  :span-method="objectSpanMethodThirdFix"
                >
                  <el-table-column label="问卷内容" rowspan="2" align="center">
                    <el-table-column
                      prop="oone"
                      label="问题"
                      align="center"
                      width="250px"
                    ></el-table-column>
                    <el-table-column
                      prop="otwo"
                      label="子项"
                      align="center"
                      width="100px"
                    ></el-table-column>

                        <el-table-column
                          v-for="(column, index) in dynamicColumns"
                          :key="index"
                          :prop="column.prop"
                          :label="column.label"
                          align="center"
                        >
                          <template v-slot="scope">
                            <MathInput
                              :disabled="true"
                              :isTable="true"
                              v-model="scope.row[column.prop]"
                            >
                            </MathInput>
                          </template>
                        </el-table-column>

                  </el-table-column>
                </el-table>
              </el-card>
            </el-col>
          </template>

//添加动态列的数据
      this.dynamicColumns.splice(0);
      let counter = 1;
      for (let i = 0; i < this.seachInfoIdList.length; i++) {
        this.dynamicColumns.push({
          prop: `othree_${counter++}`,
          label: `填写内容(${this.taskInfoIdMap.get(this.seachInfoIdList[i])})`
        });
      }
   // questionListFix 根据  上边的算法进行调整就可以了

解释

1. dynamicColumns 是动态拼接的列

原文地址：https://blog.csdn.net/qq_43071699/article/details/140514394

免责声明：本站文章内容转载自网络资源，如本站内容侵犯了原著者的合法权益，可联系本站删除。更多内容请关注自学内容网（zxcms.com）！