计算日期

#include <stdio.h>

int isLeapYear(int year) 
{
    return (year % 4 == 0 && year % 100!= 0) || (year % 400 == 0);
}

int daysFromStart(int year, int month, int day) 
{
    int days[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    int totalDays = 0;
    for (int y = 1; y < year; y++) 
{
        totalDays += isLeapYear(y)? 366 : 365;
    }
    for (int m = 1; m < month; m++) 
{
        totalDays += days[m];
        if (m == 2 && isLeapYear(year)) 
{
            totalDays += 1;
        }
    }
    totalDays += day;
    return totalDays;
}

int main() 
{
    int T;
    while (scanf("%d", &T)!=EOF)
    {
    int year[10000],month[10000],day[10000];
    for (int i=0;i<T;i++)
    {
    scanf ("%d-%d-%d",&year[i],&month[i],&day[i]);
}
        for (int i = 0; i < T; i++) 
    {
            int daysBefore = daysFromStart(year[i], month[i], day[i]);
            int days2021 = daysFromStart(2021, 1, 1);
            int result = daysBefore - days2021;
            if (result < 0) 
{
                result = -result;
            }
            result ++;
            printf ("%d\n",result);
        }
    }
    return 0;
}

原文地址：https://blog.csdn.net/ROBIN__dyc/article/details/143754569

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