Chapter04

4.6

//零存整取问题， 每月同一天存入银行50元，单利计息，月利率为5%， 求一年后的本利和

#include<stdio.h>
#define M 50 //本金
#define R 0.005   //月利率
int main() {
int i;
float sum1 = 0, sum2 = 0;

for ( i = 1; i <= 12 ; i++) //12个月一年
{
sum1 = sum1 + M;//本金和
sum2 = sum2 + sum1 * R;// 利息和
}
printf("sum1 = %.2f  sum2 = %.2f  sum1 + sum2 = %.2f", sum1, sum2, sum1 + sum2);

return 0;
}

4.8

//输入天数，输出周数和天数，例 如  输入：17， 输入 2 周 3 天

#include<stdio.h>
int main() {
int num;
printf("请输入天数：");
scanf_s("%d", &num);
if (num % 7 != 0) {

int week = num / 7;
int day = num % 7;

printf("天数%d 转换为 %d 周, %d天", num, week, day);
}
else {


int multiple = num / 7;

printf("天数%d 转化为 %d周, %d天", num, multiple, 0);
}

return 0;
}

4.9，4.10

#include<stdio.h>
#include<stdbool.h>
int ReverseInterger(int num);
int main() {
int num;
scanf_s("%d", &num);

printf("翻转前的数字为：%d\n", num);

int res = ReverseInterger(num);

printf("翻转后的数字为：%d\n", res);

return 0;
}

/// <summary>
/// 翻转一个整数
/// </summary>
/// <param name="num"></param>
/// <returns></returns>
int ReverseInterger(int num) {

int reversed = 0;
bool is_negetive = false, 

if (num == 0) return 0;

if (num < 0) {
num = -num;
is_negetive = true;
}

while (num != 0) {

int remainder = num % 10;
reversed = reversed * 10 + remainder;
num /= 10;
}

if (is_negetive) {
return -reversed;
}
else
{
return reversed;
}

}

4.11

#include<math.h>

/// <summary>
/// 计算1—10的平方和
/// </summary>
/// <returns></returns>
int CalculateSquareSum() {
int sum = 0;
for (int i = 1; i <= 10; i++)
{
sum += pow(i, 2);
}

return sum;
}

原文地址：https://blog.csdn.net/weixin_45778846/article/details/142696628

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