c语言实战-极简扫雷

C语言/c++写的C语言实战项目扫雷

结构比较清晰，仅供参考：

核心是扫雷的递归算法实现

上代码:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define SIZE 10
#define MINES 15

char board[SIZE][SIZE]; // 游戏棋盘

// 初始化棋盘，'-'表示未揭示的区域
void initBoard() {
    for (int i = 0; i < SIZE; ++i) {
        for (int j = 0; j < SIZE; ++j) {
            board[i][j] = '-';
        }
    }
}

// 在棋盘上显示当前状态
void displayBoard() {
    printf("   ");
    for (int i = 0; i < SIZE; ++i) {
        printf("%d ", i);
    }
    printf("\n");
    for (int i = 0; i < SIZE; ++i) {
        printf("%d  ", i);
        for (int j = 0; j < SIZE; ++j) {
            printf("%c ", board[i][j]);
        }
        printf("\n");
    }
}

// 随机布置地雷
void placeMines() {
    srand(time(NULL));
    int count = 0;
    while (count < MINES) {
        int x = rand() % SIZE;
        int y = rand() % SIZE;
        if (board[x][y] != '*') {
            board[x][y] = '*';
            count++;
        }
    }
}

// 检查坐标是否有效
int isValid(int x, int y) {
    return (x >= 0 && x < SIZE && y >= 0 && y < SIZE);
}

// 计算周围的地雷数量
int countAdjacentMines(int x, int y) {
    int count = 0;
    for (int i = x - 1; i <= x + 1; ++i) {
        for (int j = y - 1; j <= y + 1; ++j) {
            if (isValid(i, j) && board[i][j] == '*') {
                count++;
            }
        }
    }
    return count;
}

// 揭示某个位置的内容
void reveal(int x, int y) {
    if (!isValid(x, y)) {
        return;
    }
    if (board[x][y] != '-') {
        return;
    }
    int mines = countAdjacentMines(x, y);
    if (mines > 0) {
        board[x][y] = mines + '0';
    } else {
        board[x][y] = ' ';
        for (int i = x - 1; i <= x + 1; ++i) {
            for (int j = y - 1; j <= y + 1; ++j) {
                reveal(i, j);
            }
        }
    }
}

int main() {
    int x, y;
    char action;

    initBoard();
    placeMines();

    do {
        displayBoard();
        printf("Enter action (r for reveal, q to quit): ");
        scanf(" %c", &action);

        if (action == 'r') {
            printf("Enter coordinates (x y): ");
            scanf("%d %d", &x, &y);
            if (isValid(x, y)) {
                reveal(x, y);
            } else {
                printf("Invalid coordinates!\n");
            }
        } else if (action == 'q') {
            printf("Quitting game.\n");
            break;
        } else {
            printf("Invalid action!\n");
        }
    } while (1);

    return 0;
}

原文地址：https://blog.csdn.net/FENGCHEN____/article/details/140294888

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