Java | Leetcode Java题解之第110题平衡二叉树
题目：
题解：
class Solution {
public boolean isBalanced(TreeNode root) {
return height(root) >= 0;
}
public int height(TreeNode root) {
if (root == null) {
return 0;
}
int leftHeight = height(root.left);
int rightHeight = height(root.right);
if (leftHeight == -1 || rightHeight == -1 || Math.abs(leftHeight - rightHeight) > 1) {
return -1;
} else {
return Math.max(leftHeight, rightHeight) + 1;
}
}
}原文地址：https://blog.csdn.net/m0_57195758/article/details/139188141
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