【Dison夏令营 Day 17】使用 Python Turtle 的 24 游戏求解器
24 点 是一个数学谜题,用基本算术运算符(+、-、×、÷)将 4 个数字运算成 24。例如,给定 4 个数字 1,5,5,5,我们可以得到表达式 (5-(1÷5))×5,等于 24。
我们可以用 Python 程序暴力解决这个问题。最多有 24×5×4×4×4 = 7,680 个不同的表达式可以用 4 个数字组成。这对我们来说似乎很难,但对计算机程序来说应该很容易解决。下面是这个项目的源代码:
import turtle
screen = turtle.Screen()
screen.setup(500,500)
screen.title("24 Game Solver - PythonTurtle.Academy")
turtle.hideturtle()
turtle.speed(0)
turtle.up()
def permutation(a):
if len(a) == 1: return [[a[0]]]
res = permutation(a[1:])
r = []
for x in res:
# need to insert n into x: into all possible position
for i in range(len(x)+1):
y = x.copy()
y.insert(i,a[0])
if y not in r:
r.append(y)
return r
op = ['+', '−', '×', '÷']
def evaluate(a):
v = []
for x in a:
if type(x) is int:
v.append(x)
else:
num2 = v.pop()
num1 = v.pop()
if x=='+': v.append(num1+num2)
elif x=='−': v.append(num1-num2)
elif x=='×': v.append(num1*num2)
else:
if num2 != 0: v.append(num1/num2)
else: return 0
return v[0]
class tree_node:
def __init__(self,value,left,right):
self.value = value
self.left = left
self.right = right
def inorder(root):
if type(root.value) is int: return str(root.value)
if type(root.left.value) is not int: left = '('+inorder(root.left)+')'
else: left = inorder(root.left)
if type(root.right.value) is not int: right = '('+inorder(root.right)+')'
else: right = inorder(root.right)
return left + root.value + right
def convert_to_infix(a):
# convert to infix
# convert to tree first
v = list()
for x in a:
if type(x) is int:
v.append(tree_node(x,None,None))
else:
t2 = v.pop()
t1 = v.pop()
v.append(tree_node(x,t1,t2))
return inorder(v[0])
def twentyfour(a):
# postfix
# try n,n,n,n, p,p,p
for i in range(4):
for j in range(4):
for k in range(4):
b = a.copy()
b.append(op[i])
b.append(op[j])
b.append(op[k])
v = evaluate(b)
if v==24.0:
return(convert_to_infix(b))
# try n,n,n,p,p,n,p
for i in range(4):
for j in range(4):
for k in range(4):
b = a[:3]
b.append(op[i])
b.append(op[j])
b.append(a[3])
b.append(op[k])
v = evaluate(b)
if v==24.0:
return(convert_to_infix(b))
# try n,n,n,p,n,p,p
for i in range(4):
for j in range(4):
for k in range(4):
b = a[:3]
b.append(op[i])
b.append(a[3])
b.append(op[j])
b.append(op[k])
v = evaluate(b)
if v==24.0:
return(convert_to_infix(b))
# try n,n,p,n,p,n,p
for i in range(4):
for j in range(4):
for k in range(4):
b = a[:2]
b.append(op[i])
b.append(a[2])
b.append(op[j])
b.append(a[3])
b.append(op[k])
v = evaluate(b)
if v==24.0:
return(convert_to_infix(b))
# try n,n,p,n,n,p,p
for i in range(4):
for j in range(4):
for k in range(4):
b = a[:2]
b.append(op[i])
b.append(a[2])
b.append(a[3])
b.append(op[j])
b.append(op[k])
v = evaluate(b)
if v==24.0:
return(convert_to_infix(b))
return ''
while True:
fournumbers = []
while len(fournumbers) != 4:
numbers = screen.textinput("24 Game Solver", "Enter four numbers separated by spaces: ")
fournumbers = list(map(int,numbers.split()))
p = permutation(fournumbers)
foundsolution = False
turtle.clear()
for a in p:
r = twentyfour(a)
if len(r)>0:
turtle.goto(0,0)
turtle.color('royal blue')
turtle.write(r,font=('Courier', 45, 'bold'), align='center')
foundsolution = True
break
if not foundsolution:
turtle.color('red')
turtle.write("No solution",font=('Courier', 45, 'bold'), align='center')
原文地址:https://blog.csdn.net/weixin_41446370/article/details/140385823
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